g^2+15g=76

Solution for g^2+15g=76 equation:

g^2+15g=76

We move all terms to the left:

g^2+15g-(76)=0

a = 1; b = 15; c = -76;
Δ = b2-4ac
Δ = 152-4·1·(-76)
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{529}=23$
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-23}{2*1}=\frac{-38}{2}
=-19
$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+23}{2*1}=\frac{8}{2}
=4
$